Aptitude Test 2
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 Total number of questions : 15
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 Question 1 of 15
1. Question
1 pointsCorrectAnswer: Option B
Solution: Here s={1,2,3,4,5,6}
Let e be the event of getting the multiple of 3
Then, e={3,6}
P(e) = n(e)/n(s) = 2/6 = 1/3
IncorrectAnswer: Option B
Solution: Here s={1,2,3,4,5,6}
Let e be the event of getting the multiple of 3
Then, e={3,6}
P(e) = n(e)/n(s) = 2/6 = 1/3

Question 2 of 15
2. Question
1 points.
A man sitting in a train which is traveling at 50 kmph observes that a goods train, traveling in opposite direction, takes 9 seconds to pass him. If the goods train is 280 m long, find its speed?
CorrectAnswer: Option A
Solution: Relative speed = 280/9 m / sec = ((280/9)*(18/5)) kmph = 112 kmph.
Speed of goods train = (112 – 50) kmph = 62 kmph.
IncorrectAnswer: Option A
Solution: Relative speed = 280/9 m / sec = ((280/9)*(18/5)) kmph = 112 kmph.
Speed of goods train = (112 – 50) kmph = 62 kmph.

Question 3 of 15
3. Question
1 points.
A man can row 40 km upstream and 55 km downstream in 13 hours also, he can row 30 km upstream and 44 km downstream in 10 hours. Find the speed of the man in still water and the speed of the current.
CorrectAnswer: Option D
Solution: Let rate upstream = x km/hr and rate downstream=y km/hr.
Then, 40/x +55/y = 13…(i) and 30/x +44/y =10
Multiplying (ii) by 4 and (i) by 3 and subtracting , we get: 11/y=1 or y=11.
Substituting y=11 in (i),we get: x=5.
Rate in still water =1/2(11+5)kmph=8 kmph
Rate of current=1/2(115)kmph = 3 kmph
IncorrectAnswer: Option D
Solution: Let rate upstream = x km/hr and rate downstream=y km/hr.
Then, 40/x +55/y = 13…(i) and 30/x +44/y =10
Multiplying (ii) by 4 and (i) by 3 and subtracting , we get: 11/y=1 or y=11.
Substituting y=11 in (i),we get: x=5.
Rate in still water =1/2(11+5)kmph=8 kmph
Rate of current=1/2(115)kmph = 3 kmph

Question 4 of 15
4. Question
1 points.
Bangalore and Ooty are two stations 390 km apart. A train starts from Bangalore at 10 a.m. and travels towards Ooty at 65 kmph. Another train starts from Ooty at 11 a.m. and travels towards Bangalore at 35 kmph. At what time do they meet?
CorrectAnswer: Option C
Solution: Suppose they meet x hours after 10 a.m. Then,
(distance moved by first in x hrs) + [distance moved by second in (x1) hrs]=390. _{ }
65x + 35(x1) = 390 ==> 100x = 425 ==> x = 17/4
So, they meet 4 hrs.15 min. After 10 a.m i.e., at 2.15 p.m.
IncorrectAnswer: Option C
Solution: Suppose they meet x hours after 10 a.m. Then,
(distance moved by first in x hrs) + [distance moved by second in (x1) hrs]=390. _{ }
65x + 35(x1) = 390 ==> 100x = 425 ==> x = 17/4
So, they meet 4 hrs.15 min. After 10 a.m i.e., at 2.15 p.m.

Question 5 of 15
5. Question
1 pointsCorrectAnswer: Option B
Solution: This series is being built up according to the order where the actual term = 2^{n} – 1, with n being the number of term.
1^{st} Term = 2^{1} – 1 = 2 – 1 = 1
2^{nd} Term = 2^{2} – 1 = 4 – 1 = 3
3^{rd} Term = 2^{3} – 1 = 8 – 1 = 7
==>
7^{th} Term = 2^{7} – 1 = 128 – 1 = 127
IncorrectAnswer: Option B
Solution: This series is being built up according to the order where the actual term = 2^{n} – 1, with n being the number of term.
1^{st} Term = 2^{1} – 1 = 2 – 1 = 1
2^{nd} Term = 2^{2} – 1 = 4 – 1 = 3
3^{rd} Term = 2^{3} – 1 = 8 – 1 = 7
==>
7^{th} Term = 2^{7} – 1 = 128 – 1 = 127

Question 6 of 15
6. Question
1 points.
An uneducated retailer marks all its goods at 50% above the cost price and thinking that he will still make 25% profit, offers a discount of 25% on the market price. What is the actual profit on the sales?
CorrectAnswer: Option A
Solution: Let Cost price = Rs. 100. Then, Marked price = Rs. 150
Sales Price=75% of Rs. 150 = Rs. 112.50
Hence, gain% = 12.50%
IncorrectAnswer: Option A
Solution: Let Cost price = Rs. 100. Then, Marked price = Rs. 150
Sales Price=75% of Rs. 150 = Rs. 112.50
Hence, gain% = 12.50%

Question 7 of 15
7. Question
1 points.
A mixture contains alcohol and water in the ratio 4 : 3. If 5 liters of water is added to the mixture, the ratio becomes 4: 5. Find the quantity of alcohol in the given mixture.
CorrectAnswer: Option C
Solution: Let the quantity of alcohol and water be 4x litres and 3x litres respectively
==> 4x/(3x+5) =4/5 ==> 20x = 4(3x+5) ==> 8x=20==> x = 2.5 liters.
IncorrectAnswer: Option C
Solution: Let the quantity of alcohol and water be 4x litres and 3x litres respectively
==> 4x/(3x+5) =4/5 ==> 20x = 4(3x+5) ==> 8x=20==> x = 2.5 liters.

Question 8 of 15
8. Question
1 points.
The length of a room is 6m and the length is twice the breadth. If the area of the floor is 162m^{2}, find the area of the four walls of the room.
CorrectAnswer: Option C
Solution: Let l, b, h be the length, breadth and height of the room respectively.
Given h= 6m. and l=2b.
Area of the floor =lb =162
2b^{2} = 162, since l=2b
b^{2} = 81
b = 9m, l =18m, h =6m.
Area of four walls= 2h(l + b)
= 2×6(18+9) = 12×27 = 324m^{2}IncorrectAnswer: Option C
Solution: Let l, b, h be the length, breadth and height of the room respectively.
Given h= 6m. and l=2b.
Area of the floor =lb =162
2b^{2} = 162, since l=2b
b^{2} = 81
b = 9m, l =18m, h =6m.
Area of four walls= 2h(l + b)
= 2×6(18+9) = 12×27 = 324m^{2} 
Question 9 of 15
9. Question
1 points.
Find The number of students who can sit in a class room with length 20m and breadth 9m, if each student requires a space of 90cm × 80m.
CorrectAnswer: Option A
Solution: Number of students = Area of the room/ Area of space required for 1 student
= (20 x 100 x 9 x 100)/ (90 x 80) = 250 students.
IncorrectAnswer: Option A
Solution: Number of students = Area of the room/ Area of space required for 1 student
= (20 x 100 x 9 x 100)/ (90 x 80) = 250 students.

Question 10 of 15
10. Question
1 points.
The average age of 30 kids is 9 years. If the teacher’s age is included, the average age becomes 10 years. What is the teacher’s age?
CorrectAnswer: Option B
Solution: Total age of 30 children = 30 × 9 = 270 yrs.
Average age of 30 children and 1 teacher = 10 yrs
Total of their ages = 31 × 10 = 310 yrs
Teacher’s age = 310 – 270 = 40 Years
IncorrectAnswer: Option B
Solution: Total age of 30 children = 30 × 9 = 270 yrs.
Average age of 30 children and 1 teacher = 10 yrs
Total of their ages = 31 × 10 = 310 yrs
Teacher’s age = 310 – 270 = 40 Years

Question 11 of 15
11. Question
1 pointsCategory: Time & Work.
If 12 man can do a piece of work in 36 days. In how many days 18 men can do the same work?
CorrectAnswer: Option D
Solution: 12 men can do a work in 36 days.
18 men can do the work in (12/18 ) x 36 = 24 days.
IncorrectAnswer: Option D
Solution: 12 men can do a work in 36 days.
18 men can do the work in (12/18 ) x 36 = 24 days.

Question 12 of 15
12. Question
1 pointsCategory: Time & Work.
A, B and C earn Rs.120 per day while A and C earn Rs.80 per day and B and C earn Rs.66 per day. Find C’s earning only.
CorrectAnswer: Option C
Solution: (A+B+C) earn per day Rs.120⇒ (1)
(A+C) earn per day Rs.80⇒ (2)
(B+C) earn per day Rs.66 ⇒ (3)
From (1) and (2), we find that B earns Rs.40
From (3) we get, that C earns 26 since B earns Rs.40
IncorrectAnswer: Option C
Solution: (A+B+C) earn per day Rs.120⇒ (1)
(A+C) earn per day Rs.80⇒ (2)
(B+C) earn per day Rs.66 ⇒ (3)
From (1) and (2), we find that B earns Rs.40
From (3) we get, that C earns 26 since B earns Rs.40

Question 13 of 15
13. Question
1 points.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance traveled by him is
CorrectAnswer: Option D
Solution: Let the actual distance traveled be x km.
Then x/10=(x+20)/14
==> 14x = 10x + 200
==> 4x = 200
==> x = 50 kmIncorrectAnswer: Option D
Solution: Let the actual distance traveled be x km.
Then x/10=(x+20)/14
==> 14x = 10x + 200
==> 4x = 200
==> x = 50 km 
Question 14 of 15
14. Question
1 points.
Paulson spends 75% of his income. His income is increased by 20% and he increased his expenditure by 10%. Find the percentage increase in his savings .
CorrectAnswer: Option A
Solution: Let the original income = Rs.100 . Then , expenditure = Rs.75 and savings = Rs.25
New income = Rs.120 , New expenditure = Rs.((110/100)*75) = Rs.165/2
New savings = Rs.(120(165/2)) = Rs.75/2
Increase in savings = Rs.((75/2)25) = Rs.25/2
Increase %= ((25/2)*(1/25)*100)% = 50%.
IncorrectAnswer: Option A
Solution: Let the original income = Rs.100 . Then , expenditure = Rs.75 and savings = Rs.25
New income = Rs.120 , New expenditure = Rs.((110/100)*75) = Rs.165/2
New savings = Rs.(120(165/2)) = Rs.75/2
Increase in savings = Rs.((75/2)25) = Rs.25/2
Increase %= ((25/2)*(1/25)*100)% = 50%.

Question 15 of 15
15. Question
1 pointsCorrectAnswer: Option B
Solution: The pattern is + 5, + 7, + 9, + 11,….
IncorrectAnswer: Option B
Solution: The pattern is + 5, + 7, + 9, + 11,….
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